Sams Teach Yourself C in 24 Hours (73 page)

BOOK: Sams Teach Yourself C in 24 Hours
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printf(“The content assigned to the union separately:\n”);

/* access to name */

strcpy(dish.name, “Sweet and Sour Chicken”);

/* access to price */

dish.price = 9.95;

printf(“Dish Name: %s\n”, dish.name);

printf(“Dish Price: %5.2f\n”, dish.price);

return 0;

}

2. The following is one possible solution:

/* 20A02.c */

#include

union employee {

int start_year;

int dpt_code;

int id_number;

};

void DataDisplay(union employee u);

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487

main(void)

{

union employee info;

/* initialize start_year */

info.start_year = 1997;

DataDisplay(info);

/* initialize dpt_code */

info.dpt_code = 8;

DataDisplay(info);

/* initialize id */

info.id_number = 1234;

DataDisplay(info);

return 0;

}

/* function definition */

void DataDisplay(union employee u)

{

printf(“Start Year: %d\n”, u.start_year);

printf(“Dpt. Code: %d\n”, u.dpt_code);

B

printf(“ID Number: %d\n”, u.id_number);

}

The output of the program is

OUTPUT
Start Year: 1997

Dpt. Code: 1997

ID Number: 1997

Start Year: 8

Dpt. Code: 8

ID Number: 8

Start Year: 1234

Dpt. Code: 1234

ID Number: 1234

3. The following is one possible solution:

/* 20A03.c */

#include

#include

struct survey {

char name[20];

union {

char state[32];

char country[32];

} place;

};

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488

Appendix B

void DataEnter(struct survey *s);

void DataDisplay(struct survey *s);

main(void)

{

struct survey citizen;

DataEnter(&citizen);

DataDisplay(&citizen);

return 0;

}

/* definition of DataDisplay() */

void DataDisplay(struct survey *ptr)

{

printf(“\nHere is what you entered: \n”);

printf(“Your name is %s.\n”, ptr->name);

printf(“You are from %s.\n”, ptr->place.state);

printf(“\nThank you!\n”);

}

/* definition of DataEnter() */

void DataEnter(struct survey *ptr)

{

char is_yes[4];

printf(“Please enter your name:\n”);

gets(ptr->name);

printf(“Are you a U. S. citizen? (Yes or No)\n”);

gets(is_yes);

if ((is_yes[0] == ‘Y’) ||

(is_yes[0] == ‘y’)){

printf(“Enter the name of the state:\n”);

gets(ptr->place.state);

} else {

printf(“Enter the name of your country:\n”);

gets(ptr->place.country);

}

}

The following is the output of the program on my machine:

OUTPUT
Please enter your name:

Tony

Are you a U. S. citizen? (Yes or No)

Yes

Enter the name of the state:

Texas

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489

Here is what you entered:

Your name is Tony.

You are from Texas.

Thank you!

4. The following is one possible solution:

/* 20A04.c */

#include

#include

struct bit_field {

int yes: 1;

};

struct survey {

struct bit_field flag;

char name[20];

union {

char state[32];

char country[32];

} place;

};

B

void DataEnter(struct survey *s);

void DataDisplay(struct survey *s);

main(void)

{

struct survey citizen;

DataEnter(&citizen);

DataDisplay(&citizen);

return 0;

}

/* function definition */

void DataEnter(struct survey *ptr)

{

char is_yes[4];

printf(“Please enter your name:\n”);

gets(ptr->name);

printf(“Are you a U.S. citizen? (Yes or No)\n”);

gets(is_yes);

if ((is_yes[0] == ‘Y’) ||

(is_yes[0] == ‘y’)){

printf(“Enter the name of the state:\n”);

gets(ptr->place.state);

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490

Appendix B

ptr->flag.yes = 1;

} else {

printf(“Enter the name of your country:\n”);

gets(ptr->place.country);

ptr->flag.yes = 0;

}

}

/* function definition */

void DataDisplay(struct survey *ptr)

{

printf(“\nHere is what you’ve entered:\n”);

printf(“Name: %s\n”, ptr->name);

if (ptr->flag.yes)

printf(“The state is: %s\n”,

ptr->place.state);

else

printf(“Your country is: %s\n”,

ptr->place.country);

printf(“\nThanks and Bye!\n”);

}

Hour 21, “Reading and Writing with Files”

Quiz

1. The first expression tries to open an existing binary file called test.bin for reading and writing. The second expression tries to open an existing text file called test.txt for appending. The last expression tries to create a text file, called test.ini, for reading and writing.

2. The fopen() function returns a null pointer when an error occurs during the procedure of opening a file. It’s not legal to do any reading or writing with a null file pointer. Therefore, the code is wrong because it calls fgetc() when fopen() returns a null pointer.

3. The mode is set to read only, but the code tries to write a character to the opened file by calling the fputc() function.

4. The code still reads a text file by using the file pointer fptr1, even though the file pointer fptr1 has been closed.

Exercises

1. The following is one possible solution:

/* 21A01.c */

#include

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491

enum {SUCCESS, FAIL};

int CharRead(FILE *fin);

main(void)

{

FILE *fptr;

char filename[]= “haiku.txt”;

int reval = SUCCESS;

if ((fptr = fopen(filename, “r”)) == NULL){

printf(“Cannot open %s.\n”, filename);

reval = FAIL;

} else {

printf(“\nThe total character number is %d.\n”,

CharRead(fptr));

fclose(fptr);

}

return reval;

}

/* definition of CharRead() */

int CharRead(FILE *fin)

B

{

int c, num;

num = 0;

while ((c=fgetc(fin)) != EOF){

putchar(c);

++num;

}

return num;

}

2. The following is one possible solution:

/* 21A02.c */

#include

#include

enum {SUCCESS, FAIL, MAX_LEN = 80};

void LineWrite(FILE *fout, char *str);

main(void)

{

FILE *fptr;

char str[MAX_LEN+1];

char filename[32];

int reval = SUCCESS;

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Appendix B

printf(“Please enter the file name:\n”);

gets(filename);

printf(“Enter a string:\n”);

gets(str);

if ((fptr = fopen(filename, “w”)) == NULL){

printf(“Cannot open %s for writing.\n”, filename);

reval = FAIL;

} else {

LineWrite(fptr, str);

fclose(fptr);

}

return reval;

}

/* definition of LineWrite() */

void LineWrite(FILE *fout, char *str)

{

fputs(str, fout);

printf(“Done!\n”);

}

3. The following is one possible solution:

/* 21A03.c */

#include

enum {SUCCESS, FAIL};

void CharWrite(FILE *fout, char *str);

main(void)

{

FILE *fptr;

char filename[]= “test_21.txt”;

char str[]= “Disk file I/O is fun.”;

int reval = SUCCESS;

if ((fptr = fopen(filename, “w”)) == NULL){

printf(“Cannot open %s.\n”, filename);

reval = FAIL;

} else {

CharWrite(fptr, str);

fclose(fptr);

}

return reval;

}

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493

/* function definition */

void CharWrite(FILE *fout, char *str)

{

int i, c;

i = 0;

while ((c=str[i]) != ‘\0’){

putchar(c);

fputc(c, fout);

i++;

}

}

4. The following is one possible solution:

/* 21A04.c */

#include

#include

enum {SUCCESS, FAIL};

void BlkWrite(FILE *fout, char *str);

main(void)

{

B

FILE *fptr;

char filename[]= “test_21.txt”;

char str[]= “Disk file I/O is tricky.”;

int reval = SUCCESS;

if ((fptr = fopen(filename, “w”)) == NULL){

printf(“Cannot open %s.\n”, filename);

reval = FAIL;

} else {

BlkWrite(fptr, str);

fclose(fptr);

}

return reval;

}

/* function definition */

void BlkWrite(FILE *fout, char *str)

{

int num;

num = strlen(str);

fwrite(str, sizeof(char), num, fout);

printf(“%s\n”, str);

}

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494

Appendix B

Hour 22, “Using Special File Functions”

Quiz

1. Yes. The two statements are equivalent.

2. No. The two statements are not equivalent, unless the current file position indicator is indeed at the beginning of the file.

3. The scanf() function reads from the test.txt file, instead of the default input stream, because the freopen() function has redirected the input stream and associated it with the test.txt file.

4. The four double data items together are going to take 32 bytes in the binary file, if the size of the double data type is eight bytes long.

Exercises

1. The following is one possible solution:

/* 22A01.c */

#include

enum {SUCCESS, FAIL, MAX_LEN = 80};

void PtrSeek(FILE *fptr);

long PtrTell(FILE *fptr);

void DataRead(FILE *fptr);

int ErrorMsg(char *str);

main(void)

{

FILE *fptr;

char filename[]= “LaoTzu.txt”;

int reval = SUCCESS;

if ((fptr = fopen(filename, “r”)) == NULL){

reval = ErrorMsg(filename);

} else {

PtrSeek(fptr);

fclose(fptr);

}

return reval;

}

/* function definition */

void PtrSeek(FILE *fptr)

{

long offset1, offset2, offset3;

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495

offset1 = PtrTell(fptr);

DataRead(fptr);

offset2 = PtrTell(fptr);

DataRead(fptr);

offset3 = PtrTell(fptr);

DataRead(fptr);

printf(“\nRe-read the paragraph:\n”);

/* re-read the third sentence */

fseek(fptr, offset3, SEEK_SET);

DataRead(fptr);

/* re-read the second sentence */

fseek(fptr, offset2, SEEK_SET);

DataRead(fptr);

/* re-read the first sentence */

fseek(fptr, offset1, SEEK_SET);

DataRead(fptr);

}

/* function definition */

long PtrTell(FILE *fptr)

B

{

long reval;

reval = ftell(fptr);

printf(“The fptr is at %ld\n”, reval);

return reval;

}

/* function definition */

void DataRead(FILE *fptr)

{

char buff[MAX_LEN];

fgets(buff, MAX_LEN, fptr);

printf(“%s”, buff);

}

/* function definition */

int ErrorMsg(char *str)

{

printf(“Cannot open %s.\n”, str);

return FAIL;

}

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Appendix B

2. The following is one possible solution:

/* 22A02.c */

#include

enum {SUCCESS, FAIL, MAX_LEN = 80};

void PtrSeek(FILE *fptr);

long PtrTell(FILE *fptr);

void DataRead(FILE *fptr);

int ErrorMsg(char *str);

main(void)

{

FILE *fptr;

char filename[]= “LaoTzu.txt”;

int reval = SUCCESS;

if ((fptr = fopen(filename, “r”)) == NULL){

reval = ErrorMsg(filename);

} else {

PtrSeek(fptr);

fclose(fptr);

}

return reval;

}

/* function definition */

void PtrSeek(FILE *fptr)

{

long offset1, offset2, offset3;

offset1 = PtrTell(fptr);

DataRead(fptr);

offset2 = PtrTell(fptr);

DataRead(fptr);

offset3 = PtrTell(fptr);

DataRead(fptr);

printf(“\nRe-read the paragraph:\n”);

/* re-read the third sentence */

fseek(fptr, offset3, SEEK_SET);

DataRead(fptr);

/* re-read the second sentence */

fseek(fptr, offset2, SEEK_SET);

DataRead(fptr);

/* re-read the first sentence */

rewind(fptr); /* rewind the file position indicator */

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