XSLT 2.0 and XPath 2.0 Programmer's Reference, 4th Edition (485 page)

Read XSLT 2.0 and XPath 2.0 Programmer's Reference, 4th Edition Online

Authors: Michael Kay

BOOK: XSLT 2.0 and XPath 2.0 Programmer's Reference, 4th Edition
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Let's see how this rule works by testing it against some common cases:

  • If the pattern is
    title
    then a node matches the pattern if the node is included in the result of the expression
    root(.)//(title)
    which is the same as
    //title
    . This expression selects all
    <br/></span>elements in the document, so a node matches the pattern if and only if it is a<br/><span><title><br/></span>element.<br/></li><li>If the pattern is<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />chapter|appendix<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>then a node matches the pattern if it is selected by the expression<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />root(.)//(chapter|appendix)<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>This expression is equivalent to<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />//chapter | //appendix<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>and matches all<br/><span><chapter><br/></span>and<br/><span><appendix><br/></span>elements in the document.<br/></li><li>If the pattern is<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />/<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>then a node matches if it is selected by the expression<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />root(.)//(/)<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>This rather strange XPath expression selects the root node of every descendant of the root node, and then eliminates duplicates: so it is actually equivalent to the expression<br/><span><img src="/files/04/27/65/f042765/public/ll.gif" />/<br/><img src="/files/04/27/65/f042765/public/gg.gif" /></span>which selects the root node only. (There are complications if the root node is not a document node, for example if it is a parentless element. I will cover these complications later in the chapter: see page 688.)<br/></li></ul></div> </div> <div class="col-xs-12 text-left pagination-container"> <ul class="pagination"><li class="prev"><a href="/book/read-online-xslt-20-and-xpath-20-programmers-reference-4th-edition-free/page-484" data-page="483">«</a></li> <li class="first"><a href="/book/read-online-xslt-20-and-xpath-20-programmers-reference-4th-edition-free" data-page="0">1</a></li> <li class="disabled"><span>...</span></li> <li><a href="/book/read-online-xslt-20-and-xpath-20-programmers-reference-4th-edition-free/page-241" data-page="240">241</a></li> <li class="disabled"><span>...</span></li> <li><a href="/book/read-online-xslt-20-and-xpath-20-programmers-reference-4th-edition-free/page-480" data-page="479">480</a></li> <li><a href="/book/read-online-xslt-20-and-xpath-20-programmers-reference-4th-edition-free/page-481" data-page="480">481</a></li> <li><a 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x1="203.8669" y1="-27.309" x2="117.1669" y2="59.391" gradientTransform="matrix(1.0039 0 0 -1.0039 0.1922 516.5609)"> <stop offset="0" style="stop-color:#FFF2EB;stop-opacity:0"/> <stop offset="1" style="stop-color:#D3B4A0"/> </linearGradient> <polygon style="fill:url(#SVGID_8_);" points="169.168,470.705 154.009,455.545 94.004,455.545 94.004,470.705 "/> <linearGradient id="SVGID_9_" gradientUnits="userSpaceOnUse" x1="123.3299" y1="58.463" x2="123.3299" y2="-32.907" gradientTransform="matrix(1.0039 0 0 -1.0039 0.1922 516.5609)"> <stop offset="0" style="stop-color:#FCC344"/> <stop offset="1" style="stop-color:#F7AE3D"/> </linearGradient> <path style="fill:url(#SVGID_9_);" d="M146.114,511.368l-19.591-10.378c-1.574-0.834-3.461-0.834-5.035,0l-19.591,10.378 c-3.581,1.897-7.895-0.699-7.895-4.752v-51.07h60.004v51.07C154.009,510.668,149.695,513.264,146.114,511.368z"/> </svg> <div><a href="/book/read-online-the-silver-siren-free">The Silver Siren</a> by <span>Chanda Hahn</span></div></div><div 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